Suppose the population of trout in a certain stretch of a river is 4000. in about how many years will the population of trout be 700 if the decay rate is 35%? use the equation 700 = (4000)(0.65)x and round the value of x to the nearest year.

4 years

Step-by-step explanation:

The exponential decay equation is given by :_

, where A is the initial population and r is the rate of decay in x years .

The initial population of trout in a certain stretch of a river =4000

The rate of decay = 35% =0.35

To find the number of years (x) for the population of trout be 700, we put all the values of the above equation, we get

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

yo answer should be 6 if im not mistaken

step-by-step explanation: