Need help can anyone help me???

  it is greater than 45°

Step-by-step explanation:

From the relationship of angles and secants/tangents, we have ...

  m∠GSO = (long arc GO -arc GT)/2

Solving for (long arc GO), we have ...

  2(m∠GSO) +arc GT = (long arc GO)

We know that (long arc GO) > 180°, so we can write ...

  2(m∠GSO) +90° > 180° . . . . arc GT = 90°

  2(m∠GSO) > 90° . . . . . . subtract 90°

  m∠GSO > 45° . . . . . . . . divide by 2

Alternate solution

Inscribed ∠GOT has half the measure of arc GT, so is 45°.

You know that if angle G were 90°, then the right triangle would be isosceles, and angle S would also be 45°. In this triangle, arc GTO is less than 180°, so angle G is less than 90°.

When angle G gets smaller, the sum of angles remains the same, so angle S must be larger than 45°.

This reasoning is written more formally in the math above.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq