The diagram shows a track composed of a rectangle with a semicircle on
each end. The area of the rectangle is 3,600 square meters. What is the
perimeter of the track? Use 3.14 for 1.
The perimeter of the track is
(Round to the nearest tenth as needed.)

4856m²

Step-by-step explanation:

3600 / 90 = 40

diameter of the two circles = 40

area of a circle = πr²

radius = 40/2 = 20

20*20 = 400 / 3.14 = 1256

the 2 semicircles = 1 whole circle, no need to divide by 2

3600 + 1256 = 4856m²

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.