Miguel has to take two quizzes tomorrow. He has only enough time to study

for one of them.

• The history quiz has 4 true-or-false questions.

• The science quiz has 3 multiple-choice questions.

Miguel calculates the probability that he will get all the questions correct by

guessing.

To get 100% correct:

P(guess is correct)

History

Answer 4 of 4 correctly.

0.5

Science

Answer 3 of 3 correctly.

0.2

Miguel will study for the quiz on which he is likely to do worse by guessing.

Which quiz should he study for?

O

A. History, because he must get more questions correct.

B. Science,

C. History,

Option B is correct.

Miguel should study for the Science quiz as he will do worse in that quiz by guessing.

Step-by-step explanation:

Miguel has to take two quizzes

1) 4 true or false questions on History with a 0.5 chance of acing the quiz

Expected number of correct questions = np

n = number of questions

p = probability of acing the test

Expected number of correct questions = 4 × 0.5 = 2

2) 3 multiple choice questions on Science with a 0.2 chance of acing the quiz.

Expected number of correct questions = 0.2 × 3 = 0.6

It is evident that guessing would yield a worse result in the Science quiz with less than 1 question expected to be correct than history, where he is still expected to get 2 questions correctly by guessing.

Hope this Helps!!!

answer: the common difference is -0.10

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.