Mr. Anderson has 4 recipes for granola. Which recipe has the greatest ratio of honey to oats?

Recipe 3 has the greatest honey to oats ratio amongst the 4 recipes.

Step-by-step explanation:

Complete Question

Mr. Anderson has 4 recipes for granola. Recipe 1

A 2-column table with 3 rows is titled Recipe 1. Column 1 is labeled Honey (tablespoons) with entries 5, 10, 15. Column 2 is labeled Oats (cups) with entries 2, 4, 6.

Recipe 2

A 2-column table with 3 rows is titled Recipe 2. Column 1 is labeled Honey (tablespoons) with entries 6, 10, 14. Column 2 is labeled Oats (cups) with entries 3, 5, 7.

Recipe 3

A 2-column table with 3 rows is titled Recipe 3. Column 1 is labeled Honey (tablespoons) with entries 3, 6, 9. Column 2 is labeled Oats (cups) with entries 1, 2, 3.

Recipe 4

A 2-column table with 3 rows is titled Recipe 1. Column 1 is labeled Honey (tablespoons) with entries 8, 10, 12. Column 2 is labeled Oats (cups) with entries 4, 5, 6.

Which recipe has the greatest ratio of honey to oats?

Solution

Computing the ratio of honey to oats for each of recipes

Recipe 1

Honey | 5 | 10 | 15

Oats | 2 | 4 | 6

Honey to Oats ratio = (5/2) = (10/4) = (15/6) = 2.5 to 1.

Recipe 2

Honey | 6 | 10 | 14

Oats | 3 | 5 | 7

Honey to Oats ratio = (6/3) = (10/5) = (14/7) = 2 to 1.

Recipe 3

Honey | 3 | 6 | 9

Oats | 1 | 2 | 3

Honey to Oats ratio = (3/1) = (6/2) = (9/3) = 3 to 1.

Recipe 4

Honey | 8 | 10 | 12

Oats | 4 | 5 | 6

Honey to Oats ratio = (8/4) = (10/5) = (12/6) = 2 to 1.

Recipe 3 evidently has the greatest honey to oats ratio amongst the 4 recipes.

Hope this Helps!!!

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.