A cylindrical swimming pool has a height of 4 feet and a circumference of about 75.36 feet. What is the area of a vertical cross section through the center of the pool? Use 3.14 for π.

The Area is

Step-by-step explanation:

This problem bothers on the mensuration of solid ans flat shapes, cylinder and rectangle.

If you take a deeper look into this problem you will observe that the vertical cross section of the pool is a rectangular shape (flat).

in the rectangular shape, the length is the height of the pool

the width is the radius of the pool.

Given Data

Radius r =  ?

C= 75.36 ft

Height h=  4 ft

we need to first solve for radius r,

we know that the circumference of a circle is expressed as

we can now solve for the area of the vertical cross section which is the area of the rectangle

ryan had a head start of 10 meters.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following