Starting at time t = 0, the altitude of one helicopter is given by A1 = 600 + 150t, and the altitude of a second helicopter is given by A2 = 1250 + 50t. Which equation represents the difference of their altitudes A at time t?

The equation for difference in altitude of the two helicopters is A =  650 - 100t

Step-by-step explanation:

Given;

The altitude of one helicopter is, A1 = 600 + 150t

The altitude of a second helicopter is,  A2 = 1250 + 50t

Their difference in altitude, A at time t, is calculated as

A₂ - A₁  = A = (1250 + 50t) - (600 + 150t)

A₂ - A₁  = A =  1250 + 50t - 600 -150t

A₂ - A₁  = A = 1250 - 600 + 50t - 150t

A₂ - A₁  = A =  650 - 100t

Therefore, the equation for difference in altitude of the two helicopters is A =  650 - 100t

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2