Consider the function ƒ(x) = (x + 1)2 – 1. Which of the following functions stretches ƒ(x) vertically by a factor of 4?
Question 6 options:

A)

ƒ(x) = 4(4x + 1)2 – 1

B)

ƒ(x) = (1∕4x + 1)2 + 3

C)

ƒ(x) = 4(x + 1)2 – 1

D)

ƒ(x) = 1∕4(x + 1)2 – 4

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

21

jk it's 20

step-by-step explanation:

nope.   happens to me as well.

-aparri