What are the solutions to the equations -2t^2 +10t=0

t = 0, and t = 5; Option D

Step-by-step explanation:

For the simplicity, let us solve through factorization;

- 2t^2 + 10t = 0 ⇒ factor -2t^2 + 10t = 0, through isolation of - 2t applying exponential rule a^( b+c ) = a^b * a^c,

- 2 * t * t + 10t = 0 ⇒ rewrite 10 as 2 * 5,

- 2 * t * t + 2 * 5t = 0 ⇒ now factor -2t in - 2t^2 + 10t = 0,

- 2t( t - 5 ) = 0 ⇒ apply the zero factor principle,

- 2t = 0, and t - 5 = 0 ⇒ simplify,

Solution; t = 0, and t = 5; Option D

damm bro the struggle

step-by-step explanation:

step-by-step explanation:

the true ones are a b and d