16. Each of a group of sealed opaque envelopes contains eight bills. One envelope contains eight $1 bills, one envelope contains eight $5 bills, and one envelope contains four $1 bills and four $5 bills. An envelope is selected at random, and a bill is taken from the envelope at random. If it is a $5 bill, what is the probability that the rest of the bills in the envelope are also $5 bills

probability = 1/2

Step-by-step explanation:

Ok probability is the possibility of something happening.

So let's check the chance of $5 appearing according to how it appeared before.

4 envelopes are opened and 8 bills are inside . So total bills are 32 bills

Out of 24 bills 12 are 1$ bill

12 are $ 5 bill.

So it's a fifty fifty chance.

So the probability is 1/2

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: