Leanne is trying to convert x^2+4x-6=0 the standard form to vertex form by completing the square which equation shows the correct form

In vertex form we have y =      (x + 2)^2 - 10

Step-by-step explanation:

x^2+4x-6=0 is in standard form; we want it in the form y - k = a(x - h)^2.

Complete the square within  x^2+4x-6=0

We get  x^2 + 4x - 6 = 0  =>  x^2 + 4x + 4 - 4 - 6, or

                                          y =      (x + 2)^2 - 10

Comparing this to              y = (x - h)^2 - 10, we see that the vertex is at

                                            (h, k) :  (-2, -10)

Step-by-step explanation:

Let 0 = y to not mix up the numbers.

we are trying to get to this form:

Let's group the variables to make it easier for us to complete the square.

Complete the square by taking the number next to the x variable (4) divide it by 2 (4/2=2) and square it ()

Add this.

You also have to add it to the right side, but since we're looking to isolate y again, we're going to have to move it to the left side eventually; therefore, we can simply change the sign and add it to the left side.

In other words, instead of doing this:

I'm going to directly say the opposite of +4 is -4

Now factor the parentheses and combine like terms;

And like we said y = 0, so change that...

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

answer: the answer is ann