Shota is a dangerous fellow who likes to go rock climbing in active volcanoes. One time, when he was 30 meters below the edge of a volcano, he heard some rumbling, so he decided to climb up out of there as quickly as he could. He climbed up at a constant rate. After 4.5 seconds, he was 7.5 meters below the edge of the volcano. How fast did Shota climb? In total, how long did it take Shota to reach the edge of the volcano?

Shota's speed = 5 m/s

In total, it take 6 seconds to reach the edge of the volcano.

Step-by-step explanation:

Given;

Total height below the edge of the volcano = 30 m

(Note that he climbed at constant rate)

After 4.5 seconds, he was 7.5 meters below the edge of the volcano.

Time = 4.5 s

Distance covered = 30 - 7.5 = 22.5 m

His speed = distance covered/time

Substituting the values;

Speed = 22.5/4.5

Speed = 5 m/s

Time needed to reach the edge;

Time = distance/speed

Speed = 5m/s

Distance = 30 m

Substituting;

Time = 30/5 = 6 seconds

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.