Tia is going to create another sculpture that has the same dimensions, but it will not be hollow. She plans to use wood for the new sculpture. What dimensions of the triangular prism will Tia need to know in order to determine the amount of wood she will need for the sculpture? Explain.

Answer is below.

Step-by-step explanation:

Tia has to know the dimensions needed to find the volume of the sculpture. She needs to know the area of the base as well as the height of the pyramid. The formula that she has to use is 1/3*B*h.

This is the sample answer on EDGE 2020

Step-by-step explanation:

To know the amount of wood needed for the new sculpture, Tia will have to calculate the volume of the pyramid. To do this, she will need to know the area of the base and the height of the pyramid.

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.