An account is opened with $7,595.96 with a rate of increase of 2% per year. After 1 year, the bank account contains
$7,746.90. Assuming no deposits or withdrawals are made, which equation can be used to find y, the amount of money in
the account after x years? (Round money values to the nearest penny.)
O y = 7,746.90(1.02)*
O y = 7,746.90(0.02)*
O y = 7,595.96(1.02)*
O y = 7,595.96(0.02)*

ITS d i took the test

Step-by-step explanation:

C

Step-by-step explanation:

It's C

Step-by-step explanation:

y = 7,595.96(1.02)x

the initial beginning value times .02 after adding 1 to it so you would get 1.02 instead since it's an increase raised by x which indicates how many years it was to reach the new value.

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9