A data set is normally distributed with a mean of 115 and a standard deviation of 23. What is the probability that a value in the data set is greater than or equal to 162?
The probability is about __

The probability that a value in the data set is greater than or equal to 162

P(X≥162) = 0.0207

Step-by-step explanation:

Step(i):-

Given mean of the Population = 115

Given standard deviation of the Population = 23

Let 'x' be the random variable of normal distribution

Let x = 162

z = 2.043

Step(ii):-

The probability that a value in the data set is greater than or equal to 162

P(X>x) = P(Z>z) = P(Z> 2.043)

P(X≥162) = P(Z≥2.043) = 1-P(Z≤ 2.043)

                                      =  1- ( 0.5 +A(2.043)

                                      =   1-0.5 -A(2.043)

                                      =    0.5 - 0.4793

                                      =  0.0207

Final answer:-

The probability that a value in the data set is greater than or equal to 162

P(X≥162) = 0.0207

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.