: Mark all of the pairs of angles that are complementary. A m∠A=35° and m∠B=65° m ∠ A = 35 ° and m ∠ B = 65 ° B m∠A=21° and m∠B=69° m ∠ A = 21 ° and m ∠ B = 69 ° C m∠A=42° and m∠B=38° m ∠ A = 42 ° and m ∠ B = 38 ° D m∠A=45° and m∠B=45° m ∠ A = 45 ° and m ∠ B = 45 °

(B) m∠A=21° and m∠B=69°

(D) m∠A=45° and m∠B=45°

Step-by-step explanation:

Two angles are complementary if they sum up to 90 degrees.

(A) m∠A=35° and m∠B=65°

m∠A+m∠B=35°+65°=100°

(B) m∠A=21° and m∠B=69°

m∠A+m∠B=21°+69°=90°

(C) m∠A=42° and m∠B=38°

m∠A+m∠B=42°+38°=80°

(D) m∠A=45° and m∠B=45°

m∠A+m∠B=45°+45°=90°

We can see that only Options B and D gives a result of 90 degrees,

Therefore, the pairs in Options B and D are Complementary.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

asdsaddsa

step-by-step explanation: