I’ve actually been struggling with this:
For $n>0$, $\lbrace s_i\rbrace$ is said to s...
Mathematics, 29.05.2020 12:57, carvarceuanmoss
I’ve actually been struggling with this:
For $n>0$, $\lbrace s_i\rbrace$ is said to simply solve $SRS(n)$ if for all $k=0,1,...,n-1$, it is true that $s_k
$s_k = 1 + \sum_{i=0}^{n-1} \text{Ch}_{k}(s_i)$ where $\text{Ch}_k$ is the indicator function for the singleton set containing $k$.
Prove or disprove that the only simple solution that exists for $n>5$, which aren’t multiples of 3, is
$s_0=s_{n-2}=s_{n-1}=1$
$s_1=n-3$
$s_2=3$
$s_i=2$ for $2
And that there are none for $n$ which are multiples of $3$
Answers: 1
Mathematics, 21.06.2019 21:00, lollollollollol1
What is the missing statement in step 4? ? rts ? ? vtu and ? rtu ? ? vts ? rts ? ? rvs and ? rtu ? ? stv ? vrs ? ? vru and ? usr ? ? usv ? vur ? ? vus and ? uvs ? ? sru
Answers: 3
Mathematics, 21.06.2019 21:10, zahradawkins2007
Identify the initial amount a and the growth factor b in the exponential function. a(x)=680*4.3^x
Answers: 2
French, 20.09.2020 02:01
Mathematics, 20.09.2020 02:01
English, 20.09.2020 02:01
Spanish, 20.09.2020 02:01
English, 20.09.2020 02:01
History, 20.09.2020 02:01