The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown.

What is the greatest possible whole-number value of the congruent side lengths?

refer to the phôt

the length of 1 side is 14 cm

Step-by-step explanation:

obtuse triangle -> angle A > 90

isosceles triangle -> a = b

if A = 90 then  a1^2 + b1^2 = c^2              (a1,b1 is the length when A=90)

                        a1^2 + a1^2 = c^2

                        2   *    a1^2 = 20^2 = 400

                        a1 ^2 = 200

                       a1 = 14.14cm

if A>90 -> a < a1

as a is greatest whole number possible, a = 14 cm

1. minimum

2. 6400

3. eight

hope this !

2 2/3 hours duhh silly

step-by-step explanation: