1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the PERCENT of scores that are:

A) Between 90 and 100.

B) Over 110

C) Between 80 and 120

D) Less than 80

E) Between 70 and 100

F) More than 130

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

goog may have it for you

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: