If the Durbin-Watson statistic is greater than (4 − dL), then we conclude that

A. there is significant positive autocorrelation.
B. there is significant negative autocorrelation.
C. there is significant autocorrelation, but we cannot identify whether it D. is positive or negative.
the test result is inconclusive.

Option(b) is the correct answer to the given question

Step-by-step explanation:

1) If  then , there must be a positive Autocorrelation

According to it if the ratio d of durbin-watson is equal to or less than dL then it is called as Positive Autocorrelation.

2 ) if , then  it is  Inconclusive

According to it If the coefficient d of the Durbin-Watson is between dL & du then it is called as  Inconclusive.

3) if  then there is No proof of the Autocorrelation

According to it if the d  of the durbin-watson will be less than or equivalent to du then it is called as  No Autocorrelation.

4) If ) then there is No proof of the Autocorrelation

According to it if the d  of the durbin-watson will be less than or equivalent to 4- du then it is called as  No Autocorrelation.

5) If the  , then it is Inconclusive

According to it if the  d of the durbin-watson is between the then it is called as Inconclusive.

6) If the then it called as  negative Autocorrelation

According to it if the d of the durbin-watson is greater then then it is called as negative autocorrelation.

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)