What is the slope of tangent line to the curve y^2+y/x-x=5 at the point(1,2)

3/5

Step-by-step explanation:

First take the derivative of the function

You will then get -> 2y (dy/dx) + (((x)(dy/dx) - (y)(1))/(x)^2 ) -1

Solve for dy/dx

You will then get -> dy/dx = (x^2+y)/(x+2x^2y)

Now plug in (1,2) into dy/dx

You should get 3/5

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743