Niklas takes a dose of 252525 micrograms (\text{mcg})(mcg)left parenthesis, m, c, g, right parenthesis of a certain supplement each day. the supplement has a half life of 444 hours, meaning that \dfrac{1}{64} 64 1 start fraction, 1, divided by, 64, end fraction of the supplement remains in the body after each day. how much of the supplement is in niklas's body immediately after the 12^\text{th}12 th 12, start superscript, t, h, end superscript dose? round your final answer to the nearest hundredth.

Niklas takes a dose of 25 micrograms of a certain supplement each day. The supplement has a half life of 4 hours, meaning that 1/64 of the supplement remains in the body after each day. How much of the supplement is in Niklas's body immediately after the 12th dose? Round your final answer to the nearest hundredth.

The amount of the supplement in Niklas body immediately after the 12th dose is 430 micrograms to the nearest hundreth

Step-by-step explanation:

Half life is the time required for an element to decay into half of its initial size.

Given that :

The supplement has a half life of 4 hours, this implies that  it decay to half of its size every 4 hours.

∴ there are 6 stages of division in a day.

i.e

The amount of the supplement in Niklas body after the first dose (first day) can be calculated as:

=   × 25

= 0.390625 micrograms

It is said that he used the supplement daily for 12 days (12th dose),

As such ; we can estimate the amount of the supplement that is in his body immediately after the 12th dose; which is calculated as:

amount in his body per day × number of period for complete decay

= 0.390625 × 11

= 4.296875

≅4.30 micrograms

= 430 micrograms to the nearest hundreth

The amount of the supplement in Niklas body immediately after the 12th dose is 430 micrograms to the nearest hundreth

boxplot

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: