A leather store performs an observational survey of women walking through a mall. There were 30 women that walked by in an hour. Of those women, 18 were carrying purses, 12 were wearing belts, and 6 were both carrying purses and wearing belts.

What is the probability that a woman was wearing a belt, given that the woman was also carrying a purse?

P(B/C) = 0.3333

Step-by-step explanation:

let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.

The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:

P(B/C) = P(B∩C)/P(C)

Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.

So, P(C) is calculated as:

P(C) = 18 / 30 = 0.6

Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.

At the same way, P(B∩C) is equal to:

P(B∩C) = 6 / 30 = 0.2

Finally, P(B/C) is equal to:

P(B/C) = 0.2/0.6 = 0.3333

The answer is 1/3 :)

Step-by-step explanation:

hope this .

r3t40

0.6

39mph

step-by-step explanation: