There are eight teams in a league. In how many ways can the teams finish first, second, and third? (Assume
there are no ties.)

336 ways

Step-by-step explanation:

Feon the question, there are eight teams in a league and we are told to find the number of ways the teams can finish first, second, and third assuming that there are no ties.

First is 1 of 8, then 1 of 7 and finally 1 of 6.

= 8 × 7 × 6

= 336 ways

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

a) 7x=7

step-by-step explanation: