Hi!
Got two questions!
1.The mean of the numbers 43, 55, 76, y, 88 and 54 is 63.5.
What is the median?
2.The median of four numbers is 63. Three of the numbers are 60, 62 , and 92.
What is the missing numbers?
Thanks!!
be quick tho lol

1 median=60.3

2 missing number=38

Step-by-step explanation:

1 45+55+76+y+88+54/6

316+y/6=63.6

316+x381.6

x=381.6-316=65.6

2M4 =63

60-62+92+x/4=63

214+x=252

x=252-214

=38

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0