In ΔSTU, the measure of ∠U=90°, ST = 9.7 feet, and US = 4 feet. Find the measure of ∠T to the nearest degree.

We have been given that in ΔSTU, the measure of ∠U=90°, ST = 9.7 feet, and US = 4 feet. We are asked to find the measure of ∠T to the nearest degree.

First of all, we will draw a right triangle using our given information.

We can see that US is opposite to angle T and ST is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.

Now we will use arcsin to solve for measure of angle T as:

Upon rounding to nearest degree, we will get:

Therefore, the measure of angle T is approximately 24 degrees.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

step-by-step explanation: