A line passes through the point (-2, 3) and has a slope of -2. What is the equation of the line?

y = -2x -1

Step-by-step explanation:

slope intercept form is y = mx +b

m = slope, b = y intercept

point is given as ordered pair (x,y)

plug in slope into y=

y= -2x+b

plug in the point

3 = -2 * (-2) + b

3= 4 +b subtract 4 on each side

b = -1

y = -2x -1

the answer would be 0.54

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west