Find all the real numbers a, so that the following limit exists.

L=

Calculate the value of L and a

Step-by-step explanation:

In order for the limit to exist at x=-2, the denominator factor of (x+2) must be canceled by a numerator factor of (x+2). Synthetic division (see below) shows the remainder when the numerator is divided by (x+2) is (15-a). In order for that remainder to be zero, so that (x+2) is a factor, we must have ...

__

The same synthetic division shows the other numerator factor to be ...

  (3x +(a -6))

For a=15, this is ...

  (3x +9)

and the expression becomes ...

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: