Los números de teléfonos celulares constan de 10 dígitos, ¿cuántos números diferentes se pueden tener si el primer dígito no debe ser 0, 2 ni 4 y el segundo 4, 6 ni 8?

There are 49,000,00,000 possible numbers.

49,000,00,000 números diferentes posibles.

Step-by-step explanation:

If we have n trials, each with m possible outcomes, the total number of possible outcomes is:

In this question:

The first two trials(numbers), 3 digits are not possible in each. So 7 are possible.

The last eight numbers, all 10 digits are possible.

Then

There are 49,000,00,000 possible numbers.

49,000,00,000 números diferentes posibles.

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation:

answer: you need the equation in the question so i can answer it

step-by-step explanation: