Mathematics, 27.05.2020 23:09, idk7193

The probability that a person in the United States has type A positive blood is 31%. Three unrelated people in the United states are selected at random. Find the following probabilities. Round your answers to the thousandths place. A) Find the probability that all three have type A positive blood. B) Find the probability that none of the three have A positive blood. C) Find the probability that at least one of the three have A positive blood. D) Which of the events above can be considered unusual? Explain your reasoning.

Answers: 3

Show answers

Answers

answered: MathChic68

(A) Probability that all three have type A positive blood is 0.0298.

(B) Probability that none of the three have type A positive blood is 0.3285.

(D) The events which can be considered unusual is of the first part (A).

Step-by-step explanation:

We are given that the probability that a person in the United States has type A positive blood is 31%.

Three unrelated people in the United states are selected at random.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 3 people

r = number of success

p = probability of success which in our question is probability that

a person in the United States has type A positive blood, i.e; 31%

Let X = Number of people in the United States has type A positive blood

So, X ~ Binom(n = 3, p = 0.31)

(A) Probability that all three have type A positive blood is given by = P(X = 3)

P(X = 3) = $\binom{3}{3} \times 0.31^{3} \times (1-0.31)^{3-3}$

= $1 \times 0.31^{3} \times 0.69^{0}$

= 0.0298

(B) Probability that none of the three have type A positive blood is given by = P(X = 0)

P(X = 0) = $\binom{3}{0} \times 0.31^{0} \times (1-0.31)^{3-0}$

= $1 \times 1\times 0.69^{3}$

= 0.3285

P(X $\geq$ 1) = 1 - P(X = 0)

= 1 - 0.3285

= 0.6715

(D) The events above which can be considered unusual is of the first part (A) whose probability is less than 5% because an event is considered unusual whose probability is less than 5%.

Since, the probability of all three people having type A positive blood is 2.98%, so this event is considered to be unusual.

answered: Guest

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

answered: Guest

answer: answer: d) v= 1/6 bh

step-by-step explanation:

since according to the given question, a pyramid is placed inside a prism.

step-by-step explanation:

Other questions on the subject: Mathematics

Mathematics, 21.06.2019 14:50, ayoismeisalex

Name the most appropriate metric unit for each measurement like a length of an carrot

Answers: 2

continue

Mathematics, 21.06.2019 15:30, ayoismeisalex

Kylie explained that (-4x+9)^2 will result in a difference of squares because (-4x+9)^2 (-4x+9)^2 =(-4x)^2+(9)^2=16x^2+81

Answers: 3

continue

Mathematics, 21.06.2019 20:00, christpress0

Given the equation y − 4 = three fourths(x + 8) in point-slope form, identify the equation of the same line in standard form. −three fourthsx + y = 10 3x − 4y = −40 y = three fourthsx + 12 y = three fourthsx + 10

Answers: 1

continue

Mathematics, 21.06.2019 20:30, ultimatesaiyan

Answer asap ill give ! ’ a sample of radioactive material decays over time. the number of grams, y , of the material remaining x days after the sample is discovered is given by the equation y = 10(0.5)^x. what does the number 10 represents in the equation? a. the half-life of the radioactive material, in days b. the amount of the sample, in grams, that decays each day c. the time, in days, it will take for the samples to decay completely d. the size of the sample, in grams, at the time the material was discovered

Answers: 1

continue

Do you know the correct answer?

The probability that a person in the United States has type A positive blood is 31%. Three unrelated...