What is the 7th term in the sequence below? 3,12,48,192

This is a geometric sequence...so we first find the common ratio by dividing the 2nd term by the 1st term. 12/3 = 4...so the common ratio is 4.

an = a1 * r^(n-1)
n = term to find = 7
a1 = first term = 3
r = common ratio = 4
now we sub
a7 = 3 * 4^(7-1)
a7 = 3 * 4^6
a7 = 3 * 4096
a7 = 12288 <===