The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm. a. Find the probability that an individual distance is greater than 218.40 cm. b. Find the probability that the mean for 25 randomly selected distances is greater than 203.50 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

12*c

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead