Determine the function’s value when x = −1.

g(x) = x3 + 6x2 + 12x + 8

g(-1) = 1

Step-by-step explanation:

Using " ^ " to denote exponentiation, we get:

g(x) = x^3 + 6x^2 + 12x + 8

Substituting -1 for x, we get:

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8, or

g(-1) = -1 + 6 - 12 + 8, or

g(-1) = 1

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐