High-definition (HD) televisions today have a 16 : 9 aspect ratio (width to height). The advertised screen size is equal
to the screen diagonal.
Allowing for 2 inches of Styrofoam padding on all sides of the TV, what is the smallest possible length and width of a
shipping box for a 75-inch HD TV?

A)60 by 45
B)68 by 40
C)64 by 36
D)75 by 44

B)68 by 40

Step-by-step explanation:

First we multiply this ratio by any whole number 16 : 9 . At least to get close to the option.

So I multiplied by 4

Giving me 64:36

So we remember that there is a padding of on both sides of the length and width.

This padding is 2 inch each

It's going to be

= 64+(2+2):36+(2+2)

= 68:40

The most correct option is;

B) 68 by 40

Step-by-step explanation:

Here we have that the advertised screen size = Screen diagonal

Size of the HD TV = 75-inch

Therefore, diagonal of HD TV = 75-inch

Where the width of the HD TV = w

The height of the HD TV = h

h² + w² = 75²

w/h = 16/9

w = 16/9×h

∴ h² + (16/9×h)² = 75²

337/81×h² = 75²

h = 36.8 in.

Therefore, w = 16/9×36.8 = 65.4 in.

Hence when the thickness of the Styrofoam cup is added, we have;

2 inches on both sides gives 4 inches to be added to both height and width

Which gives,height = 36.8 + 4 = 40.8 in.

Width = 65.4 + 4 = 69.4 in.

The smallest possible dimensions is approximately

69.4 in. by 40.8 in.

Hence, the most correct option is B) 68 by 40.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4