(x – 3)^2 + (y + 6)^2 = 16

the radius of the circle is ?

The center is (3, -6) and the radius is 4

Step-by-step explanation:

(x – 3)^2 + (y + 6)^2 = 16

We can write the equation of a circle as

(x – h)^2 + (y -k)^2 = r^2

Where (h,k) is the center and r is the radius

(x – 3)^2 + (y -  -6)^2 = 4^2

The center is (3, -6) and the radius is 4

4

Step-by-step explanation:

By comparing with the canonical form of the equation of a circle

(X-Xo)^2 + (Y-Yo) ^2 = r^2; Xo and Yo are the coordinates of the centre of the circle

r^2= 16 >> r = 4

so what is the question

step-by-step explanation: