Write an equation in standard form of the line that passes through the given points:

1. (2, -2) and (2, 6)

2. (-3, 4) and (3, 0)

Step-by-step explanation:

The standard form for a line is Ax+By=C

First, we need to find the slope, or change in y over change in x. For the first one, this is

, which is impossible to find as we cannot divide by 0, meaning that this is constant horizontally -- in this case, x=2. Thus, we have 1*x+0*y=2.

For the second one, we can find the slope by getting

. We can then take the point (3,0) (it can be any point on the line) and get our equation to be y-0 = (-2/3) (x-3). Converting this to standard form, we can expand this to get

y= (-2/3)*x +2

(-2/3)*x+1*y = 2

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

ok

step-by-step explanation: