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Mark charged a battery. Each minute, the percentage of the battery's capacity that was charged increased by 2.5 percent. After 17 minutes of charging, the battery was 61.5 percent full.

How full was the battery when the charging began?

How long from the time that Mark started charging did it take the battery to be fully charged?

original charge=21/5%

time to full charge=32.4 min

Step-by-step explanation:

an=a+(n-1)d

61.5=a+(17-1)(2.5)

61.5=a+40

a=61.5-40=21.5

original charge=21.5 %

100=21.5+(n-1)(2.5)

100-21.5=(n-1)(2.5)

78.5=(n-1)(2.5)

n-1=(78.5)/2.5=15.7/0.5=31.4

n=31.4+1=32.4

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

rx and sx

step-by-step explanation: