Write an equation for the nth term of the geometric sequence below: (Equation NEEDS to be written as gn=7(5)^(n-1) or as gn=2/3(1/4)^(n-1) NOTICE NO SPACES & using ^ to represent an exponent)

You didn't give the geometric sequence in question.

But to find the nth term of a geometric sequence, use the formula

Sn = ar^(n - 1)

Where a is the first term of the sequence

r is the common ratio of the sequence.

Example: To find the nth term of the geometric sequence

1/2, 1/4, 1/8, 1/16, ...

Here, a = 1/2

r = 1/4 ÷ 1/2 = 1/8 ÷ 1/4 = 1/16 ÷ 1/8 = 1/2.

Sn = (1/2)(1/2)^( n - 1)

Apply this method to the sequence you were given, it will be helpful.

goog may have it for you

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18