Tristen is building 3 trophies using Legos. He needs 324 total Legos. Tristen uses 220 Legos for the largest trophy and 135 Legos for the smallest trophy. How many Legos will he use to build the final trophy

166

Step-by-step explanation:

Number of trophies = 3

Total Legos required for all trophies = 324

Number of Legos for largest trophy(A) = 220

Number of Legos for smallest trophy(B) = 135

Number of Legos required for final trophy(C)

=?

Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]

324 = 220 +135 + C

324 = 355 + C

324 - 355 = C

-31 = C

135 + 31 = 166

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v