Compute probability of randomly selected 5 cards from deck of 52 cards and getting only one Jack.

3243 / 10829 ≈ 0.2995

Step-by-step explanation:

There are 52 cards in a deck.  5 cards are selected, so the number of possible combinations is ₅₂C₅.

Of the 5 cards selected, 1 is a Jack and 4 are non-Jacks.

There are 4 Jacks in a deck.  The number of ways of choosing 1 Jack from 4 is ₄C₁.

There are 48 non-Jacks in a deck.  The number of ways of choosing 4 non-Jacks from 48 is ₄₈C₄.

So the probability is:

P = ₄C₁ ₄₈C₄ / ₅₂C₅

P = 4 × 194580 / 2598960

P = 778320 / 2598960

P = 3243 / 10829

P ≈ 0.2995

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation: