For a certain animal, suppose that the number of babies born is independent for each pregnancy. This animal has a
70%
chance of having
1
baby and a
30%
chance of having
2
babies at each pregnancy. Let
X
be a random variable that represents the total number of babies if the animal gets pregnant twice. Construct a table showing the probability distribution of
X
. Arrange
x
in increasing order.
Write the probabilities
P(x)
as decimals rounded to two decimals.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

the first option is the answer.

let's fu(!

step-by-step explanation:

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130