A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 8 tables is $58. The total cost to rent 5 chairs and 2 tables is $23. What is the cost to rent each chair and each table?

Equations::

4c + 8t = 58

2c + 3t = 23

Modify for elimination:

4c (4c*1) + 8t (8t*1)= 58

4c (2c*2) + 6t (3t*2)= 46

Subtract and solve for "t":

2t (8t-6t) = 12

t = $6 (cost of one table)

Solve for "c":

2c + 3t = 23

2c + 18 = 23

2c = 5

c = $2.50 (cost of one chair)

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b