The Service Club is choosing members at random to attend conferences in Sheboygan, Madison, La Crosse, and Green Bay. There are 15 members in the club, how many ways can they choose someone to go to the Sheboygan conference, someone different for the Madison conference, someone else for La Crosse, and one last person for Green Bay? SHOW YOUR WORK.

There are 32760 ways to pick the members

Step-by-step explanation:

For the first place you have 15 possibilities, since every member of the club is available. For Madison you will have only 14, since you cant pick the same member than the one you picked for Sheyoygan. For the same argument, you will have 13 possibilities available for La Crosse, and only 12 for Green Bay.

We have to pick a combination using the possibilities that we have, thus, you have to multiply all 4 possibilities toguether to find the amount of ways to choose members to attend the conferences. This means that you will have a total of 15*14*13*12 = 32760 possibilities in total.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)