Which point is NOT part of the solution of the inequality y < |3x| + 1? (2, –9) (0, 0) (3, 15) (–4, 12)

I think it would be (2,-9)

Step-by-step explanation:

I got three solutions which were:

( 0 , − 1 ) , ( 1 , 2 ) , ( 2 , 5 )

I'm not sure how you could get (2, –9) (0, 0) (3, 15) (–4, 12)

But, based on random logic of mine 2,-9 is the wrong one.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11