Point B has coordinates (2,1). The x-coordinate of point A is negative 1. The distance between point A and point B is 5 units. What are the possible coordinates of point A?

(-1, 5)

(-1, -3)

Step-by-step explanation:

Given that coordinates of point B = (2,1) this means, x2 = 2 & y2 = 1.

The x coordinate of point A = -1

D = 5 units

Let's use the equation for distance between points, it is expressed as:

Solving further, let's square both sides,

Solving further, we have:

For the possible values, we have:

Therefore, the possible coordinates of point A are:

(-1, 5)

(-1, -3)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !