A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn.

a. What is the probability of selecting a purple marble and then a white marble?

b. What is the probability of selecting two white marbles?

c. Is there a greater chance of selecting two white marbles in a row or two purple marbles in a row? Show your work.

pleae hlp

Step-by-step explanation:

in general, the probability of some event

= number of times that event can happen/total number of possible outcomes

so ...

you have 2 white and 7 purple

prob of purple = 7/9

then

prob of white = 2/8 , there are only 8 left since you drew one already.

prob(purple, then white) = (7/9)(2/4) = 7/36

prob(2 whites) = (2/9)(1/8) = 1/36

prob(2 purples) = 7/9(6/8) = 7/12

and of course 7/12 > 1/36

clearly , since you had more purples than whites, the chances of getting purples would be greater than the chances of getting whites.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2