I'll give brainliest to whoever answers correctly first
Which is the graph of the function f(x) = Negative StartRoot x EndRoot On a coordinate plane, an absolute value graph starts at (0, 0) and goes down and to the right through (4, negative 2). On a coordinate plane, an absolute value graph starts at (0, 0) and goes up to the left through (negative 4, 2). On a coordinate plane, an absolute value graph starts at (0, 0) and goes down and to the left through (negative 4, negative 2). On a coordinate plane, an absolute value graph starts at (0, 0) and goes up and to the right through (4, 2).

eveidence i thing that

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

kayla would of sent 8

step-by-step explanation: