If f(x) =
= 3x + 3, g(x) = 3x + 3, and h(x) = x + 3, what is [g ofo h](-5)?

  (g○f○h)(-5) = -6

Step-by-step explanation:

(g○f○h)(-5) = g(f(h(-5)))

  = g(f(-5+3)) = g(f(-2))

  = g(3(-2)+3) = g(-3)

  = 3(-3) +3 = -6

(g○f○h)(-5) = -6

by definition, an arc subtended by a central angle of some given measure has the same measure. so .

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?