Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2

The factor of 6x²y − 3xy − 24xy² + 12y² is 3y(2x - 1)(x - 4y)

Given:

6x²y − 3xy − 24xy² + 12y²

find the highest common factor of all the coefficient of each term

6 = 1, 2, 3, 6

6 = 1, 2, 3, 63 = 1, 3

6 = 1, 2, 3, 63 = 1, 324 = 1, 2, 3, 4, 6, 8, 12, 24

6 = 1, 2, 3, 63 = 1, 324 = 1, 2, 3, 4, 6, 8, 12, 2412 = 1, 2, 3, 4, 6, 8, 12

The highest common factor of all the coefficient of each term is 3

So,

6x²y − 3xy − 24xy² + 12y²

= 3y(2x² - x - 8xy + 4y)

(2x² - x - 8xy + 4y) = (2x - 1)(x - 4y)

Therefore,

6x²y − 3xy − 24xy² + 12y = 3y(2x - 1)(x - 4y)

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6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls