There are eight teams in a league. I’m how many ways can the teams finish first, second, and third?

There are 336 ways can the teams finish first, second, and third

Step-by-step explanation:

Total no. of teams = 8

First prize is given to one of the 8 teams

So, no. of teams left for second prize = 8-1 =7

Second prize is given to one of the remaining 7 teams

So, no. of teams left for third prize = 7-1=6

So,the teams finish first, second, and third in no. of ways =

The teams finish first, second, and third in no. of ways = 336

Hence there are 336 ways can the teams finish first, second, and third

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: